Помогите с решением пожалуйста.
Система неравенств
(2x+3)^2=5y
(3x+2)^2=5y;
След:
3x^2+y=5
6x^2-y=2

$left { {{2x+3)^2=5y} atop {(3x+2)^2=5y}} right. left { {{(2x+3)^2=(3x+2)^2} atop {(3x+2)^2=5y}} right. left { {{2x+3=3x+2} atop {(3x+2)^2=5y}} left { {{2x-3x=2-3} atop {(3x+2)^2=5y}} left { {{-x=-1} atop {(3x+2)^2=5y}}$

$left { {{x=1} atop {(3*1+2)^2=5y}} left { {{x=1} atop {5y=5^2}} left { {{x=1} atop {y=5}}$

$left { {{3x^2+y=5} atop {6x^2-y=2}} right. left { {{9x^2=7} atop {3x^2+y=5}} right. left { {{x^2= frac{7}{9} } atop {3x^2+y=5}} right. left { {{x^2= frac{7}{9} } atop {3*frac{7}{9} +y=5}} right.$

$left { {{x^2=frac{7}{9} } atop {3*frac{7}{9} +y=5}} right. left { {{x^2=frac{7}{9} } atop {2frac{1}{3} +y=5}} right. left { {{x= frac{+}{} frac{ sqrt{7} }{3} } atop {y=2 frac{2}{3} }} right.$