4х^4-37х^2+9=0
помогите :)

$4 x^4-37 x^{2} +9=0$
$x^{2} =t$
$4t^{2} -37t+9=0$
a=4 b=-37 c=9
D=b²-4ac=37²-4*4*9=1225=35²
$t1= frac{-b+ sqrt{D} }{2a} = frac{37+35}{8} = frac{72}{8} =9$
$t2= frac{-b- sqrt{D} }{2a} = frac{37-35}{8}= frac{2}{8} = frac{1}{4}$
x²=9 x²=1/4
x=-3 x=1/2
x=3 x=-1/2