Разложите на множители квадратный трехчлен
x^2-16x+60
x^2+20x-96
x^2-4x-77
x^2-4x-96

$x^{2} -16x +6 = 0 D = 16^{2} - 6*4 = 256-240 = 16 X1 = frac{16-4}{2} = 6 X2= frac{16+4}{2} = 10 (x - X1)(x- X2) = 0 (x-6)(x-10) = 0 $

$x^{2} +20x -96 = 0 D= 20^{2} - (-96*4)=400+384= 784 X1 = frac{-20+28}{2} = 4 X2= frac{-20-28}{2} = -24 (x -X1)(x-X2) = 0 (x-4)(x+24) = 0 $

$x^{2} -4x - 77 = 0 D= 4^{2} - (-77*4) = 16+308= 324 X1= frac{4+18}{2} = 11 X2 = frac{4-18}{2} = -7 (x -X1) (x-X2) = 0 (x-11)(x+7) = 0$

$x^{2} - 4x- 96 = 0 D= 4^{2} - (-96*4) = 400 X1= frac{4+20}{2} = 12 X2= frac{4-20}{2} = -8 (x-X1)(x-X2) = 0 (x-12)(x+8) = 0$